How Long Does a Ball Take to Fall Back Down After Being Thrown Upward?

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Homework Help Overview

The problem involves a ball being thrown vertically upward with an initial velocity and then caught at a height above the ground. The subject area pertains to kinematics and motion under gravity.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster seeks guidance on which equation of motion to use for determining the time of flight and the final velocity. Some participants suggest using a specific kinematic equation and solving a quadratic equation for time, while others question the process of solving for time.

Discussion Status

The discussion is ongoing, with participants providing hints and equations to consider. There is an exploration of the quadratic solution, but no consensus has been reached on the approach to take.

Contextual Notes

The problem is constrained by the given initial velocity, the height at which the ball is caught, and the acceleration due to gravity. Participants are discussing how to apply these values in the context of kinematic equations.

manzoor
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Homework Statement


A boy throws a ball vertically upward from the ground with the velocity 25 m/s. On its way down it is caught 5 m above the ground. How long did the trip take and with what velocity was it coming down?


Homework Equations





The Attempt at a Solution


Which equation of motion should I use? Please give me hints
 
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Use
y = Vi*t - 1/2*g*t^2.
Solve the quadratic to find t. You will get two values. For return journey, take the larger value of t.
 
What do you mean by solve the quadratic for t?
 
manzoor said:
What do you mean by solve the quadratic for t?
In the problem y is given. g is known. Initial velocity is given. Substitute these values in the kinematic equation and solve for t.
 

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