How long does a ball take to reappear at a certain point when it is thrown up?

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Homework Help Overview

The problem involves a ball being thrown upward and observed from a second-story apartment window. The ball is visible for a duration of 0.25 seconds while it travels a distance of 1.06 meters. The questions posed include determining the time it takes for the ball to reappear at the same point and calculating the maximum height above the window.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss appropriate kinematic equations for the motion of the ball and the forces acting on it during its ascent and descent. There are inquiries about which forces might be negligible in this context.

Discussion Status

The discussion is ongoing, with various participants exploring different kinematic equations and suggesting ways to simplify the problem by adjusting the coordinate system. Some guidance has been offered regarding the initial conditions of the ball's motion.

Contextual Notes

Participants are considering the effects of gravity and the time the ball is visible, while also questioning the assumptions about the forces acting on the ball during its motion.

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Homework Statement



Sitting in a second-story apartment, a physicist notices a ball moving straight upward just outside her window. The ball is visible for 0.25 s as it moves a distance of 1.06 m from the bottom to the top of the window.

How long does it take the ball to reappear?
What is the greatest height of the ball above the top of the window?

Homework Equations





The Attempt at a Solution

 
Last edited:
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What kinematic acceleration equations would you considered appropriate when describing a ball falling down from a two story building? What forces are acting upon the ball as it falls down? What forces would you consider negliglble in this scenario?
 
vf2 = vi2 + 2a\Deltax

x = xi + vit + 1/2 at2
 
Move your coordinate plane so the x-axis is on the bottom of the window. You can ignore everything that happens below the window, in fact you can pretend that the ball was launched right at the bottom of the window. You know that it took .25s to travel 1.06m so now just find Vo
 

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