On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a golf club improvised from a tool. The free-fall acceleration on the moon is of its value on earth. Suppose he hit the ball with a speed of 29 at an angle 26 above the horizontal. How long was the ball in flight? First I found out that the vertical component of the initial velocity is 29*sin(26 deg) = 12.7. Next I used the following equation, V = V0 + a*t, where a = -9.8/6. 29*sin(26 deg)*6/9.8 = t = 7.8 sec. Is this not the correct answer?