How Many Balloons Can .1m^3 He @ 150atm Blow Up?

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The discussion revolves around calculating how many balloons can be inflated from a tank containing helium gas at 150 atm and a volume of 0.1 m³. Each balloon, when filled, has a diameter of 0.3 m and is at an absolute pressure of 1.2 atm. The calculations show that approximately 884 balloons can be inflated, with a more precise calculation suggesting around 892.85 balloons. It is emphasized that the pressure in the tank must remain above 1.2 atm for filling to occur. The final conclusion highlights the importance of maintaining pressure for successful balloon inflation.
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A tank having a volume of .1 m^3 contains helium gas at 150 atm. How many balloons can the tank blow up if each filled balloon is a sphere .3 m in diameter at an absolute pressure of 1.2 atm.

Here is what I have so far: Assuming no gas gas escapes to the atmosphere during transfer, n is constant. R is constant by definition. Lastly the final volume must be a multiple of (4/3)(pi)(.3/2)^3. But this leaves me with three variables -the volume factor, and the initial and final temperatures...please help... thanks
 
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You can try assuming the temperature remains constant.
 
p1*v1=n*p2*v2

(assuming t1 = t2)

v2 = 4/3*pi*(d/2)^3
with d = 0.3m
v2 = 0.014 m^3

n = p1/p2*v1/v2

n = 150 atm/1.2atm*.1m^3/.014m^3
n = 884.194
(0.014 has more numbers after it you'll get this number if u carry them all)

so I'd say the answer is roughly 884 balloons
 
Considering both pressures are absolute, abercrombiems02 arrived nearer to the answer but calculation is wrong(that should give 892.85 balloons).

When the pressure in the tank falls to 1.2atm absolute, there will be no filling. So you should calculate 148.8*0.1/(1.2*0.014)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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