How Many BC and IC Do We Need for Different Equations?

  • Context: Undergrad 
  • Thread starter Thread starter Glass
  • Start date Start date
  • Tags Tags
    Ic
Click For Summary
SUMMARY

The discussion clarifies the necessity of boundary conditions (BC) and initial conditions (IC) for solving partial differential equations (PDEs) such as the heat equation and the wave equation. Specifically, the heat equation requires 2 BC and 1 IC due to its two spatial derivatives and one time derivative, while the wave equation necessitates 2 BC and 2 IC. The conversation also highlights that the number of conditions needed is determined by the order of derivatives in the equations, with each derivative contributing to the degrees of freedom. The choice of conditions can vary based on the physical scenario being modeled.

PREREQUISITES
  • Understanding of partial differential equations (PDEs)
  • Knowledge of boundary conditions (BC) and initial conditions (IC)
  • Familiarity with the heat equation and wave equation
  • Concept of degrees of freedom in mathematical modeling
NEXT STEPS
  • Study the derivation and applications of the heat equation
  • Explore D'Alembert's solution for the wave equation
  • Learn about different types of boundary conditions in PDEs
  • Investigate the implications of initial conditions on time evolution in physical systems
USEFUL FOR

Students and professionals in mathematics, physics, and engineering who are working with partial differential equations and need to understand the role of boundary and initial conditions in modeling physical phenomena.

Glass
Messages
24
Reaction score
0
So I'm confused on how we know we need x many BC and/or IC. For example, regarding the heat equation, we need 2 BC, and 1 IC (supposedly because there are two spatial derivatives and one time derivative). And similarly, for the Wave equation we need 2 BC and 2 IC. And another thing, why is it that when we look at D'Alembert's solution of the infinite string wave equation, why we only need 2 IC and no IC? Thanks, I'm very confused.
 
Physics news on Phys.org
Each integration supplies an arbitrary constant (or in partial differential equations, an arbitrary function of the other independent variables). Thus, for the most general solution, there are N extra degrees of freedom for each Nth-order derivative (in the heat equation, 2 for space + 1 for time; in the wave equation, 2 + 2, etc.). Therefore, in order to get to an equation that describes a specific physical situation, we need to supply additional conditions to narrow down these extra degrees of freedom.

As for exactly which additional conditions make the most sense, that depends on the physical situation. Often, we are interested in the time evolution of a system, and so it makes sense to give an initial condition for every order in the time derivatives. But it is not strictly necessary that it be so; we could, for example, give final conditions instead, if we were interested in calculating things that way.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
7
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K