How many chocolates did Angeline give to Billie

  • Context: MHB 
  • Thread starter Thread starter anemone
  • Start date Start date
Click For Summary
SUMMARY

Angeline initially had 70 more chocolates than Billie, represented as x = y + 70. After giving 20% of her chocolates (0.2x) to Billie, the equation y + 0.2x = 0.8x + 20 was established, leading to the equation x - 70 = 0.6x + 20. Solving this yields x = 90, indicating Angeline had 90 chocolates. Consequently, Angeline gave 18 chocolates to Billie, calculated as 0.2 * 90.

PREREQUISITES
  • Understanding of algebraic equations
  • Familiarity with percentage calculations
  • Ability to manipulate and solve linear equations
  • Knowledge of variable representation in word problems
NEXT STEPS
  • Study the concept of linear equations in algebra
  • Learn how to solve word problems using algebraic methods
  • Explore percentage calculations and their applications
  • Practice variable representation and manipulation in equations
USEFUL FOR

Students learning algebra, educators teaching mathematical problem-solving, and anyone interested in enhancing their skills in solving word problems involving variables and percentages.

anemone
Gold Member
MHB
POTW Director
Messages
3,851
Reaction score
115
Angeline and Billie shared some chocolates. Angeline had 70 more chocolates than Billie. After Angeline gave 20% of her sweets to Billie, Billie had 20 more chocolates than Angeline. How many chocolates did Angeline give to Billie?

(This is another word problem that can be approached by the model method...(Nod))
 
Mathematics news on Phys.org
That looks like a pretty standard "algebra" problem. Let x be the number of chocolates Angeline had and let y be the number of chocolates Billy had.

" Angeline had 70 more chocolates than Billie."
x= y+ 70 or y=x- 70.

" After Angeline gave 20% of her sweets to Billie, Billie had 20 more chocolates than Angeline."
20% of Angeline's sweets is 0.2x. After Angeline gives them to Billie she has x- 0.2x= 0.8x and Billie has y+ 0.2x sweets. y+ 0.2x= 0.8x+ 20. Subtract 0.2x from both sides to get y= 0.6x+ 20.

We have both y= x- 70 and y= 0.6x+ 20 so x- 70= 0.6x+ 20.

Solve that for x." How many chocolates did Angeline give to Billie?"
Multiply x by 0.2.
 
[TIKZ]
\draw (0,0) rectangle (2,1);
\draw (-8,0) rectangle (0,1);
\draw [<->] (-8, 1.4) -- (0.8, 1.4);
\node at (-3,1.6) {\small 4 units};
\draw [<->] (0, 1.2) -- (2, 1.2);
\node at (1,1.8) {\small 70 chocolates};
\node at (0.4,0.4) {\tiny 1 part};
\node at (1.4,0.4) {\tiny 1 unit};
\draw[thick, dotted] (0.8, 0) -- (0.8, 1);
\node at (-8.6,0.5) {\small A};
\node at (-8.6,-1) {\small B};
\draw (-8,-1.5) rectangle (0,-0.5);
\draw (0,-1.5) rectangle (1.2,-0.5);
\draw[thick, dotted] (0.8, -1.5) -- (0.8, -0.5);
\node at (0.4,-1) {\tiny 1 part};
\node at (1,-1) {\tiny 20};
\draw[very thick, dotted,green] (0,-1.5) rectangle (1.2,-0.5);
\draw[ultra thick, dotted,green] (0,-1.5) rectangle (1.2,-0.5);
\draw[ultra thick, dotted,green] (0.8,0) rectangle (2,1);
\draw[gray, thick, - >] (2.1,0.5) -- (2.2,0.5) -- (2.2,-1) -- (1.3,-1);
\draw [<->] (0,-1.7) rectangle (1.2,-1.7);
\node at (0.7,-1.85) {\tiny 1 unit};
[/TIKZ]

We are looking for the value of 1 unit.

$\begin{align*} 1 \text{ part}+1 \text{ unit}&=70\\1 \text{ part} +20&=1 \text{ unit}\\1 \text{ unit} -20&=70-1 \text{ unit}\\ 2 \text{ units}&=90\\ \therefore 1 \text{ unit}&=45\end{align*}$
 
That would be better if you had said what "one unit" and "one part" are in terms of numbers of chocolates.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
969
  • · Replies 4 ·
Replies
4
Views
3K
Replies
2
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K