How many exchanges are needed to serve a city of 80,000 people?

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SUMMARY

To serve a city of 80,000 people, a minimum of 8 exchanges is required, assuming each exchange can accommodate 10,000 unique phone numbers. The calculation is based on the structure of seven-digit phone numbers in the United States, which consist of a three-digit exchange followed by a four-digit number. Given that the first digit of the exchange cannot be 0 or 1, the total number of usable exchanges is limited, necessitating the use of combination and permutation principles to determine the exact number needed for larger populations.

PREREQUISITES
  • Understanding of seven-digit phone number structure in the United States
  • Basic knowledge of combination and permutation mathematics
  • Familiarity with the concept of area codes and exchanges
  • Ability to perform calculations involving large numbers
NEXT STEPS
  • Research the mathematical principles of combination and permutation
  • Explore the structure and allocation of area codes in telecommunications
  • Learn about the limitations of phone number assignments in the U.S.
  • Investigate how population density affects phone number distribution
USEFUL FOR

Mathematicians, telecommunications professionals, urban planners, and anyone interested in the logistics of phone number allocation in populated areas.

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A seven-digit phone number in the United States consists of a three-digit exchange followed by a four-digit number. How many exchanges are needed to serve a city of 80,000 people?


Combination, Permutation, and arrangement with repetition equations are used in this section.

Part 1 of this question I got right: 8,000,000 people can have phone numbers in one area code if the first digit of the 7 numbers can't be 0 or 1. Part 2 listed above I'm absolutely stumped on though.
 
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10,000 numbers per exchange?
 

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