Chemistry How many grams of NaCl are needed to make a 2M stock solution?

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To prepare a 2M stock solution of NaCl in 50ml, one needs to calculate the mass of NaCl required using its molecular weight of 58 g/mol. The correct approach involves using the formula n = C × V, where n is the number of moles, C is the concentration in moles per liter, and V is the volume in liters. For a 2M solution in 0.05 liters, 2 moles/L × 0.05 L equals 0.1 moles. Multiplying 0.1 moles by the molecular weight of 58 g/mol results in 5.8 grams of NaCl needed for the solution. Understanding the relationship between moles, mass, and molecular weight is crucial for accurate calculations.
liam91
You have to show your attempts at answering the question, this is a forum policy. Also, all homework like questions should go to homework forum.

Homework Statement


- How many grams of NaCl (molecular weight = 58 Da) would you have to dissolve in 50ml to make a 2M stock solution?

The Attempt at a Solution


I have thought about simply multiplying 58 by 0.1 = 5.8 g, but am not sure if this is correct.

It's just the daltons that are throwing me a bit off, also I wasn't too sure if i should be implementing n = m/M.

Thanks everyone.
 
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What relevant equations do you know?
 
liam91 said:
I have thought about simply multiplying 58 by 0.1 = 5.8 g, but am not sure if this is correct.

Where did you got 0.1 from? (Note: I am not saying it is wrong, I am just asking where it came from).
 

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