How Many Local Maxima Does F(x) = (sin(Nx)^2)/(sin(x)^2) Have?

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Homework Help Overview

The discussion revolves around the function F(x) = (sin(Nx)^2)/(sin(x)^2) and its local maxima within the interval 0 < x < π. The original poster is attempting to show that there are N-2 local maxima in this range.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster has calculated the derivative but is uncertain about simplifying the resulting equation. They mention finding 2N-1 local maxima and minima, which they believe is incorrect. Other participants suggest plotting the function for small values of N and analyzing the zeros and limits of the function.

Discussion Status

Some participants have provided insights regarding the number of zeros of the function and its behavior at the boundaries of the interval. There is a suggestion that the original poster may not need to calculate the derivative based on the zeros identified.

Contextual Notes

Participants are exploring the implications of the function's zeros and its limits at the endpoints of the interval, which may influence the understanding of local maxima. The original poster's confusion about the derivative and the number of local maxima is acknowledged.

zardiac
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1. Show that the function F(x)=(sin(Nx)^2)/(sin(x)^2) has N-2 local maxima in the interval 0<x<pi



Homework Equations





3. I am stuck after i have calculated the derivate, (2Nsin(Nx)cos(Nx)sin(x)^2-2sin(x)cos(x)sin(Nx)^2)/sin(x)^4 = 0

I am not sure how to simplify this equation, so far I have found 2N-1 local maximum and minimum, which is not correct. Please give me some hints.
 
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Try to plot the original function for small N-s. How many zeros has the original function in the interval (0, pi)?
What are the minimal values of the function? What are limits at x=0 and at x=pi?

ehild
 
Last edited:
The original function has N-1 zeros on the interval (0,pi).
The minimal values for the function is 0. And F->N^2 as x->0 and x->pi
Wich means, if there are (N-1) zeros then there is (N-1)-1 = N-2 maximum.
So I don't have to calculate the derivative.

Thanks for the help ^^
 
You have found out the solution earlier than me:smile:

ehild
 

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