How many nine-digit numbers meet these criteria?

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SUMMARY

The discussion focuses on calculating the number of nine-digit numbers divisible by 225, specifically those with all different digits and a hundred's digit of 7. To meet the divisibility criteria, the number must be divisible by 3, 5, and 17. The criteria for divisibility by 3 require that the sum of the digits is a multiple of 3, while divisibility by 5 necessitates that the last digit is either 0 or 5. The challenge lies in ensuring the number is also divisible by 17.

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  • Understanding of number theory, specifically divisibility rules.
  • Familiarity with nine-digit number properties.
  • Knowledge of combinatorial counting principles.
  • Basic arithmetic operations and digit manipulation.
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  • Research the properties of numbers divisible by 17.
  • Study combinatorial techniques for counting distinct digit arrangements.
  • Explore the rules of divisibility for 3 and 5 in greater detail.
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stamenkovoca02
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The number of nine-digit numbers divisible by 225 in which all digits are different and in which the digit of hundred is 7 is?
I don't know how to set the number to be divisible by 225, so if anyone can help
 
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255= 3(5)(17) so any number divisible by 255 must be divisible by 3, 5, and by 17. Any number divisible by 3 has digits that sum to a multiple of 3. Any number divisible by 5 has one's place 5 or 0. 17 is the hard one!
 

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