- #1

Pikkugnome

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- TL;DR Summary
- How does an uncomputable number and its rational approximation go together?

Digits of an uncomputable number, as I understand, can't be produced. However all real numbers have rational approximations. Does it mean that there exists a bound for the rational approximation. It is odd to talk about rational approximations in a non-contructive sense, but I am ok with it. I guess the most uncomputable number would the one, which none of its digts can be calculated. That is strange, since then we can't even find its lower and upper bounds, as then we would know one of its digits. I am guessing this is true, it seems obvious. On the otherhand, if the bounds themselves are uncomputable numbers...