How many people can the raft hold physics problem

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Homework Help Overview

The problem involves determining the capacity of a raft constructed from logs, specifically how many people it can support before submerging. The subject area includes principles of buoyancy and fluid mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the buoyant force and its relationship to the weight of displaced fluid. There are attempts to apply formulas related to pressure and density, along with questions about the specifics of submerged logs and their displacement.

Discussion Status

The discussion is ongoing, with participants offering hints and exploring the concept of buoyant force. Some guidance has been provided regarding the calculation of displaced water, but no consensus or resolution has been reached.

Contextual Notes

Participants are working under the assumption that the specific gravity of wood and the average mass of a person are relevant to the calculations. There is a noted uncertainty regarding the application of the buoyant force formula and how it relates to the logs' dimensions and weight.

Elvis
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CAN ANYONE HELP ME, PLEASE ! I DON'T KNOW HOW TO SOLVE THIS PROBLEM

A raft is made of 10 logs lashed together. Each is 30cm in diameter and has a length of 5.5m. How many people can the raft hold before they start getting their feet wet,assuming the average person has a mass of 70 kg? Do not neglect the weight of the logs! Assume the specific gravity of wood is 0.60.

SG=0.60
r=1/2*30=15cm

I know
F/A = mg/A
F= mg =pAHg were p-->density
p=m/v
pressure=P=F/A
 
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Hint: What's the buoyant force acting on a completely submerged log?
 


The boyanty Force is:

Fb = F2 - F1
pfgA(h2-h1)
pfgAh
pfgV

I don't know how to solve please help !
 


The buoyant force is the weight of the displaced fluid. How much water does a submerged log displace?
 

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