How Many Protons for a 5g Orbital Electron Configuration?

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Discussion Overview

The discussion revolves around determining the number of protons required for an atom to achieve a ground state electron configuration with one electron in a 5g orbital, using the n+l rule. Participants explore the implications of this rule on electron configurations and the order of filling orbitals.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant states that the g orbital corresponds to an l value of 4, leading to a total of 9 for the n+l rule, suggesting that the 5g orbital is filled after orbitals with lower n+l values.
  • Another participant asserts that a neutral atom would have an equal number of protons and electrons, proposing that 121 protons would correspond to 121 electrons.
  • A participant calculates the total number of electrons up to the 8s orbital as 120, concluding that adding one electron for the 5g orbital results in 121 protons.
  • There is uncertainty expressed regarding the necessity of the 5g orbital being preceded by the 8s orbital, with one participant questioning why it cannot be preceded by the 6d orbital instead.

Areas of Agreement / Disagreement

Participants generally agree on the calculation leading to 121 protons but express differing views on the order of orbital filling and the implications of the n+l rule, indicating unresolved aspects of the discussion.

Contextual Notes

Participants reference the Aufbau principle and the n+l rule, but there are unresolved questions regarding the specific order of orbital filling and the assumptions underlying these rules.

Razael
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Homework Statement



Using a strict interpretation of the n+l rule, how many protons would an atom need to create a ground state electron configuration with one electron in a 5g orbital? Give electron configuration.

Homework Equations




The Attempt at a Solution



g is an l value of 4, 4+5 = 9. So 5g is filled after other orbitals with n+l's lower than 9, or equal but with higher n values.

This puts 5g after 9s, does it not? I have no clue what to do from here.
 
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Atom is neutral - that means charge of electrons and charge of nucleus cancel out, they are identical (just one is positive, other negative).
 
The answer (which is given) is 121 protons. Since the atom is neutral, there'd also be 121 electron, so I'd look for an electron configuration where all orbitals before 5g + 1 = 121.

I don't know what 5g comes after though.
 
Okay, added up all electrons up to and including 8s and got 120. Adding one for 5g gives me 121.

I still don't understand why it has to be preceded by 8s though. Why not, say, 6d?
 

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