How many reactions per second are needed to produce a power output of 15 MW?

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SUMMARY

The discussion focuses on calculating the number of fusion reactions required to achieve a power output of 15 MW using the fusion reaction 2_1_H + 3_1_H --> 4_1_He + 1_0_n, which releases 17.5708 MeV of energy. The conversion of MeV to joules is essential, as 1 MeV equals 1.60218 x 10^-13 joules, leading to a total energy release of approximately 2.82 x 10^-12 joules per reaction. To produce 15 million joules per second, approximately 5.3356 x 10^18 reactions per second are necessary.

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Homework Statement


Basically, I pretty much solved the problem I am working on. The fusion reaction I am working with is 2_1_H + 3_1_H --> 4_1_He + 1_0_n, and I determined the energy the reaction releases to be 17.5708 MeV. What I need to figure out now is how many of these reactions must occur per second to produce a power output of 15 MW.


Homework Equations



I was looking through the chapter and could not figure out which equations I can put together to solve this. But I did use E = deltam x c^2 to get my answer of 17.5708 MeV.

The Attempt at a Solution



I could not determine how to set up my work for this problem after going through the chapter. I was thinking of using the conversion factor for Curies, but I did not think it was relevant to my problem I am solving.
 
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chroot said:
MeV is a unit of energy, which can be readily converted into joules.

http://www.google.com/search?hl=en&q=17.5708+MeV+in+joules&btnG=Google+Search

Next, since you need 15 MW of power, you need 15 million joules per second.

15 million joules per second, divided by the energy released by each reaction in joules, will give you reactions per second.

- Warren
This gave me an answer of 5.3356 x 10^18 reactions/s. Got it right. Thanks!
 
Last edited:

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