How to Calculate Energy Released in Fission Reaction

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SUMMARY

The forum discussion focuses on calculating the energy released in a fission reaction involving Uranium-235 and neutrons. The initial mass (mi) is calculated as 236.05259u, while the final mass (mf) totals 236.847092u, leading to a mass defect (delta m) of 0.794502u. The energy released is computed using the equation E = delta m(c^2), resulting in approximately 740.08 MeV. The user seeks clarification on incorporating intermediate products in the calculation, specifically the excited state of Uranium-236.

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Homework Statement



1_0_n + 235_92_U 140_54_Xe + 94_38_Sr + 2 1_0_n
Using the above reaction, determine the amount of energy.


Homework Equations



mi = 235.043925u + 1.008665u + 236.05259u
mf = 140.914406u + 93.915356U + 2(1.008665u) = 236.847092Uu
delta m = 0.794502
E = deltam(c^2) = (0.794505u)(931.5MeV/c^2/u)c^2 = 740.078613

The Attempt at a Solution



See above in part . My answer is incorrect. I double checked my work, and I got the same answer. Can anybody figure out what I'm doing wrong? Thanks.
 
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Compare:

mi = 235.043925u + 1.008665u

m (U-236) = 236.05259u

mf = 140.914406u + 93.915356U + 2(1.008665u)


235U + n -> 236U* -> FP + 2n
 
Okay, how do I incorporate the middle product into my equation? The book wasn't too good with explaining that part.
 

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