How Many Real Solutions Does the Function f(x)=1.1x^4-6.7x^2+7.9x-2 Have?

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SUMMARY

The function f(x) = 1.1x^4 - 6.7x^2 + 7.9x - 2 has been analyzed for the number of real solutions to the equation f(c) = 0. Participants in the discussion concluded that the function likely has three real roots, as indicated by the number of x-intercepts observed on its graph. The confusion arose from misinterpreting the evaluation of f(0) instead of directly determining the roots of the function. Graphical analysis is essential for accurately identifying the number of solutions.

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screamtrumpet
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Homework Statement


The graph of f(x)=1.1x^4-6.7x^2+7.9x-2 satisfies the equation f(c)=0 for how many real values of c?




Homework Equations





The Attempt at a Solution


1.1(0*^4)-.7(0)^2+7.9(o)-2
1 real value of c?
 
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You can't sub in 0. You're looking for numbers c such that f(c) = 0, not what the values of f(0) are.
 
screamtrumpet said:

Homework Statement


The graph of f(x)=1.1x^4-6.7x^2+7.9x-2 satisfies the equation f(c)=0 for how many real values of c?

The Attempt at a Solution


1.1(0*^4)-.7(0)^2+7.9(o)-2
1 real value of c?
They didn't ask for f(0), which is what you calculated. The question is, how many solutions are there for the equation f(c) = 0?
 
so do you plug in c?
 
You can't plug in c - you don't know what c is. I suspect that they intend for you to look at the graph of this function and see how many x-intercepts there are.
 
it looks like it intercepts injb 3 places
 

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