(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 5.0m diameter merry go round is initially turning with a 4.0s period. It slows down and stops in 20 s. How many revolutions does the merry go round make as it stops?

2. Relevant equations

w=v/r

v=2(pi)r/T

3. The attempt at a solution

v=2(pi)2.5/4

=3.9 m/s

w=v/r

= 3.9/2.5

=1.56 rad/s

1.56 rad/s X (1rev/2(pi)rad)=2.48 rev

how is the answer 24.8??? I don't understand....Please help

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# How many revolutions does the merry go round make as it stops?

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