How Many Sodium Atoms Remain in the 3p State After 10ns?

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Homework Help Overview

The discussion revolves around the behavior of sodium atoms in an excited state, specifically the 3p state, and their decay over time. The original poster presents a problem involving the number of sodium atoms remaining in the 3p state after a specified time and the number of photons emitted during a given interval.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of the exponential decay formula to determine the number of sodium atoms remaining in the excited state and the number of emitted photons. There are questions about the correctness of the calculations and the implications of the lifetime of the excited state on the results.

Discussion Status

Some participants have confirmed the setup of the equations as appropriate, while others have raised concerns about the precision of the numerical results and the assumptions made regarding photon emission. The conversation indicates a productive exploration of the topic without reaching a definitive consensus.

Contextual Notes

Participants note that the lifetime of the excited state is a mean value and that real-world results may vary. There is also mention of the potential for multiple photon emissions, although this is considered less likely.

fredrick08
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Homework Statement


1x10^6 sodium atoms are excited to the 3p state at t=0s. The lifetime of the 3p state is 17ns.

a.how many of these atoms remain in the 3p state at t=10ns?
b.how many photons have been emitted from t=0s to t=30ns?


Homework Equations


N=Noe^(-t/[tex]\tau[/tex])


The Attempt at a Solution


a. N=1x10^6*e^(-10ns/17ns)=5.55x10^5 sodium atoms
b. N=1x10^6*e^(-30ns/17ns)=171237 sodium atoms
thus N-No=828763 sodium atoms undergo quantum jump during the first 30ns, each of these atoms emits a photon, thus 828763 photons are emitted.

Im not sure if these are correct, but can't find where I've gone wrong, is it ok to do it like that and that the fact that the 17ns lifetime... doesn't have any effect on the 30ns... please can someone confirm that I am right or help me where i have gone wrong thanks.
 
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fredrick08 said:

Homework Statement


1x10^6 sodium atoms are excited to the 3p state at t=0s. The lifetime of the 3p state is 17ns.

a.how many of these atoms remain in the 3p state at t=10ns?
b.how many photons have been emitted from t=0s to t=30ns?

Homework Equations


N=Noe^(-t/[tex]\tau[/tex])

The Attempt at a Solution


a. N=1x10^6*e^(-10ns/17ns)=5.55x10^5 sodium atoms
b. N=1x10^6*e^(-30ns/17ns)=171237 sodium atoms
thus N-No=828763 sodium atoms undergo quantum jump during the first 30ns, each of these atoms emits a photon, thus 828763 photons are emitted.

Im not sure if these are correct, but can't find where I've gone wrong, is it ok to do it like that and that the fact that the 17ns lifetime... doesn't have any effect on the 30ns... please can someone confirm that I am right or help me where i have gone wrong thanks.

The lifetime here I believe is the mean lifetime. Results in nature may vary over a set of 106.

The equations you've set up look ok to me. Assuming only 1 photon is available in the 3p of each to go to the 3s, then your answer would seem to be good.
 
Yes, there is only one photon "available" to go from 3p to 3s. More precisely, the Na atom could also decay by emitting 3 photons (each with roughly a third of the energy difference between 3p and 3s), but that process is much much much less likely.

I would deduct points though for using way too many digits in your answer.
 
ok then thanks very much for ur help
 

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