How many electrons in the ground state of a Hg atom

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Discussion Overview

The discussion centers around determining how many electrons in the ground state of a mercury (Hg) atom can have the quantum number ml = +1. Participants explore the electron configuration of Hg and the implications of quantum numbers, particularly in relation to filled orbitals and their capacities.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested, Homework-related

Main Points Raised

  • One participant states the electron configuration for Hg as [Xe]6s^2 5d^10 and attempts to count the subshells that can have ml = +1, concluding with a total of 10 electrons.
  • Another participant challenges this approach, suggesting that the initial reasoning is missing key elements and asks for a list of filled orbitals in Hg that may have ml = +1.
  • A participant later claims to arrive at a count of 12 but expresses confusion about the next steps needed to reach a final answer.
  • Another participant questions the validity of the answer key that states there are 16 electrons with ml = +1, expressing skepticism about how this number could be correct.
  • Participants discuss the filled orbitals in Hg, with one noting that all orbitals except for 1s could potentially have ml = +1.
  • Clarifications are made regarding the quantum numbers, with a participant mistakenly associating ml = +1 with the 2s orbital, which is corrected to refer to the 2p orbital instead.
  • Eventually, one participant suggests that the count of orbitals that are not "s" could lead to a total of 16 electrons, as each of these orbitals can hold 2 electrons.
  • Another participant confirms this reasoning, indicating that the calculation aligns with the earlier confusion.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct number of electrons with ml = +1, with some suggesting 10 or 12, while others propose 16 based on different interpretations of the filled orbitals.

Contextual Notes

Participants express uncertainty regarding the definitions and implications of quantum numbers, particularly in relation to the filled orbitals of Hg. There are unresolved steps in the reasoning that lead to different conclusions about the total count of electrons.

Who May Find This Useful

Students studying atomic structure, quantum mechanics, or preparing for exams in chemistry or physics may find this discussion relevant.

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How many electrons in the ground state of a Hg atom can have the quantum number ml = +1?


The way I am trying to figure this out is as follows..

Electron configuration for HG is..
[Xe]6s^2 5d^10
n=6
l : ml
0: 0
1: -1,0,1
2: -2,-1,0,1,2
3 -3,-2,-1,0,1,2,3
4 -4,-3,-2,-1,0,1,2,3,4
5: -5,-4,-3,-2,-1,0,1,2,3,4,5

so ml can = +1 where l=1-5
Thats a total of 5 subshells that can have ml=+1.

If each subshell can hold two electrons, then the answer must be 10 right?
But apparently it is actually 16. Can someone please explain to me how it is 16?
 
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You were already told at other forum how to approach the problem. You were already told what your approach is missing. Repeating question here in hope that someone will do it for you won't help.

List all orbitals (2p, 3d and so on) that are:

1. filled in Hg
2. may have ml = +1

--
methods
 
I did, and I get 12. I don't know where to go from here, if someone can just walk me through to the solution that's all I need.

I am stumped, and got no replies at that other forum. I do believe a new forum will render new replies...
I appreciate your trying to guide me, but I simply do not follow what you are trying to tell me.

Can you please try explaining this another way, or can someone else please explain how to do it?
 
Does nobody know how to do this?

I am inclined to believe that my answer key is wrong, and 16 is not the answer. It is either 10 or 12 I guess.

I don't see how you can possibly get 16...
 
Can you list ALL filled orbitals in Hg?

--
methods
 
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^14 5d^10

It looks like every orbital is in fact filled.
And they all could have ml=+1 except for the 1s orbital.

Now what?
 
2s can have ml=+1?

What is n for 2s? l? Possible values of ml?

--
 
Last edited:
n for 2s = 2

where n=2
l= 0,1
ml can = +1 where l = 1

If I count all the subshells that can hold ml=+1 (basically everything with n=2 or higher) then multiply by two, I get a waaay bigger number.
 
Sorry to be naggy, but I really need to understand this fast. I have a final tomorrow morning!

Thanks!
 
  • #10
n=2 & l=1 is not 2s, it is 2p.

--
methods
 
  • #11
I understand that. But I still do not see how to get 16.

Can you please just walk me through this?
 
  • #12
I think I see it. We are counting all the orbitals that are NOT "s" right? Each holds 2 electrons, that's 8x2=16?yyaay?
 
  • #13
Yes. Wasn't that hard?

--
methods
 
  • #14
nah.

Thanks a lot Borek, I <3 you.
 

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