How many subsets does set A have?

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SUMMARY

The discussion centers on calculating the number of subsets and proper subsets of the set A = {1, 2, 3}. The total number of subsets is determined using the formula 2^n, where n is the number of elements in the set. For set A, which contains three elements, the total number of subsets is 8, while the number of proper subsets is 7, as it excludes the set itself. Participants confirm the correctness of these calculations and clarify the definitions of subsets and proper subsets.

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lipun4u
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Let 's Consider a set A where A={1,2,3}

Can anyone tell me
1>no of subsets of A
2>no of proper subsets of A

Regards,
Asit
 
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lipun4u said:
Let 's Consider a set A where A={1,2,3}

Can anyone tell me
1>no of subsets of A
2>no of proper subsets of A

Regards,
Asit

What have you tried already? If you know the definition of subset, it should be easy enough to make a list of all the subsets and then count them. There is also a very simple formula relating the number of subsets of a given set to its cardinality.

After you answer part 1, part 2 is simply the number of subsets of A minus the number of those sets which are not proper subsets. (what is the definition of proper subset?)
 
i know the asnwer

if A has three elements, proper subset of A will be 7
becoz all the subsets will be Null,{1},{2},{3},{1,2},{2,3},{1,3}
subsets of A will be 8 BY INCLUDING {1,2,3}

I asked it, becoz i m not sure ab it.

Am i correct ab it ??
 
the formula for the cardinality of the powerset is 2^(cardinality of the set) hence the number is 8 not 7
 
i m saying ab proper subset not subset...
 
lipun4u said:
i know the asnwer

if A has three elements, proper subset of A will be 7
becoz all the subsets will be Null,{1},{2},{3},{1,2},{2,3},{1,3}
subsets of A will be 8 BY INCLUDING {1,2,3}

I asked it, becoz i m not sure ab it.

Am i correct ab it ??

Yes, that's correct.
 
ice109 said:
the formula for the cardinality of the powerset is 2^(cardinality of the set) hence the number is 8 not 7

If a set, A, contains n members, then it has 2n subsets. Since that includes A itself, which is not a proper subset of itself, A has 2n-1 proper subsets. (And A has 2n-2 proper, nonempty subsets.)
 

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