How Many Trips Does a Bird Make Between Two Trains Before Getting Sandwiched?

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Homework Help Overview

The problem involves two trains moving towards each other on the same track, with a bird flying back and forth between them until it becomes sandwiched. The subject area includes concepts from kinematics and infinite series.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the mathematical implications of the bird's trips being infinite while questioning the assumptions about the bird's size and the changing velocities of the trains. Some suggest using geometric series or constant speed calculations to analyze the situation.

Discussion Status

The discussion is exploring various interpretations of the problem, including the implications of the bird's size and the mathematical modeling of its motion. Some participants have offered insights into potential approaches, but there is no explicit consensus on how to resolve the issues raised.

Contextual Notes

Participants note the importance of accounting for the bird's size and the dynamics of the trains' motion, which may affect the mathematical model used to analyze the problem.

Rainbow
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Here’s a question that I’m stuck with.
Two trains initially separated by distance L are heading towards each other on the same track each with speed v, and a bird flies from train A towards B with constant speed w>v reaches train B and immediately comes back to A with same speed and continues to do so till it sandwiches between the two. Find out the number of trips and time taken before it sandwiches.
I solved it mathematically and got the answer as infinity, which I find hard to accept. I think this is due to the wrong mathematical approach. I mean, at some point of time the velocities of both the trains and the bird change to zero. So, I think we would have to account for this sudden change of variables in our equations. But, the question is how.
 
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Mathematically it is infinite because your bird instantaneously changes direction and is zero length.
Factor in the fact that at each turn the bird must decelerate to zero, turn and accelerate back to w. When the period of time between the trains is less than the turning time and the distance between the trains is less than the birds length the bird is squashed.
 
The number of back and fore trips is infinite, but the time taken and the distance it covers is quite finite.

There are two ways to approach it, either using a geometric series and summing an infinite number of convergent terms or by realising that the bird moves at a constant speed the entire time and that you can calculate the time to collision simply from the train's motion.

This is a rewording of a question often attributed to Von Neumann.
 
I think your mathematic model fails because you did not take into account the size of the bird. At a certain point, when distance is equal to the bird size, the model must stop the iteration.
 

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