How many walls can this battery-powered crane lift before recharging?

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Homework Help Overview

The discussion revolves around a battery-powered crane's ability to lift a certain number of walls before needing a recharge. The problem involves calculating the number of walls based on the crane's energy capacity and the potential energy required to lift the walls to a specified height.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the crane's energy capacity and the potential energy required to lift the walls. There are attempts to derive a formula for the number of walls, N, based on the given parameters. Questions arise regarding the mass of the walls and how it factors into the calculations.

Discussion Status

Participants are actively engaging with the problem, sharing their equations and questioning the assumptions made about the mass of the walls. There is recognition of errors in previous solutions, and some participants are exploring how to express the mass in terms of other variables. The discussion is ongoing with no clear consensus yet.

Contextual Notes

There is mention of a previous exercise that provides a specific mass for the walls, but participants are uncertain about its applicability to the current problem. The discussion reflects a need for clarity on how to incorporate this information into their calculations.

MichaelTam
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Homework Statement
Exercise
Relevant Equations
PE=mgh,
A new, innovative type of crane is battery powered. Its battery has a total energy capacity U , expressed in Joule. Determine how many walls, N of mass m , the crane can lift before the battery has 20% left and needs to be recharged. The walls need to be lifted from /h_1/ to /h_2/ a new location at height . You may assume that energy is only used when the walls are lifted and you may disregard any energy losses.
 
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My solution is incorrect, but I still can’t find out the error….
 
MichaelTam said:
My solution is incorrect, but I still can’t find out the error….
What about the mass of each wall?
 
N=0.8*U/(g*(h_2-h_1)), you may see it at the second post
 
MichaelTam said:
N=0.8*U/(g*(h_2-h_1)), you may see it at the second post
I see it now.

PeroK said:
What about the mass of each wall?
 
each wall has a mass of m but N is the sum of those mass.
 
MichaelTam said:
each wall has a mass of m but N is the sum of those mass.
N is the number of walls.
 
But I cannot express N as variable m
 
  • #10
the last exercise tells me m=1000kg, but I don’t know if I can substitute that into this situation or not.
 
  • #11
MichaelTam said:
But I cannot express N as variable m
What does that mean? The walls have mass ##m## which determines the energy needed to lift them.
 
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  • #12
‘That’ means the last exercise it mention m is equal to 1000kg, I think I doesn’t work in this exercise.
 
  • #13
I use the equation of
1.Potential energy = N*m*g*(h_2-h_1)
2.Energy of the battery can be used = (1-20%)*U
(1) = (2)
Then I find N=N=0.8*U/(m*g*(h_2-h_1)) but how can I express m in terms of other variable?
 
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  • #14
MichaelTam said:
I use the equation of
1.Potential energy = N*m*g*(h_2-h_1)
2.Energy of the battery can be used = (1-20%)*U
(1) = (2)
Then I find N=N=0.8*U/(m*g*(h_2-h_1))
That's the answer.

MichaelTam said:
but how can I express m in terms of other variable?
I don't understand this question.
 
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  • #15
I found the system is coming up with a error, the solution can be include m now, I’m sorrry….
 

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