How Many Ways Can You Solve This Permutation Problem?

  • Thread starter Thread starter bllnsr
  • Start date Start date
  • Tags Tags
    Permutation
Click For Summary

Homework Help Overview

The discussion revolves around a permutation problem, where participants are evaluating different approaches to calculating the number of ways to arrange items based on a given scenario. The original poster presents several answers and seeks validation of their correctness.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the validity of the original poster's answers, with some suggesting alternative calculations and questioning the assumptions behind the original answers. There is a focus on clarifying the interpretation of the problem statement.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's attempts. Some guidance has been offered regarding the need for more detailed explanations of the methods used. Multiple interpretations of the problem are being explored, particularly concerning the calculations presented.

Contextual Notes

There is a mention of a potential misunderstanding of the problem, which may affect the answers provided. Participants are encouraged to clarify their reasoning and assumptions in their attempts.

bllnsr
Messages
26
Reaction score
0

Homework Statement


http://i49.tinypic.com/2hoeghs.png

Homework Equations



The Attempt at a Solution


(i) 144 ways
(ii) 2!*4!*3!
(iii) 12*5!
these are my answers
 
Physics news on Phys.org
looks ok

what is worrying you about that? :confused:​
 
are my answers correct?
 
They look correct to me.
 
Ok Thanks
 
Generally, for 'The Attempt At A Solution' you should show what you actually did, not just list the answers.
 
@HallsofIvy
sorry for that next time I will post my full attempt.
 
Shouldn't the answer to (i) be 1440

5P3 * 4! = 1440

The rest look fine to me.
 
hms.tech said:
Shouldn't the answer to (i) be 1440

5P3 * 4! = 1440

The rest look fine to me.
No, it's 4!3!. How do you get 1440?
 
  • #10
I think you right, I made a mistake understanding the question .
Thanks
 

Similar threads

Is My Approach to Solving This Permutation Problem Correct?
  • · Replies 16 ·
Replies
16
Views
3K
Solving using permutation and combination
  • · Replies 5 ·
Replies
5
Views
2K
Permutations with possibly repeating letters
  • · Replies 4 ·
Replies
4
Views
3K
How do I determine the sign of this permutation
  • · Replies 4 ·
Replies
4
Views
2K
Finding no. of combinations for the situation
  • · Replies 5 ·
Replies
5
Views
2K
Are pq and qp always 3-cycles?
  • · Replies 2 ·
Replies
2
Views
2K
How Do You Calculate Permutations for Complex Problems?
  • · Replies 1 ·
Replies
1
Views
1K
Cards and envelopes permutation problem
  • · Replies 10 ·
Replies
10
Views
4K
Permutation and Combination Problem
  • · Replies 4 ·
Replies
4
Views
2K
In how many ways can 5 prizes be given away to 4 boys?
  • · Replies 16 ·
Replies
16
Views
3K