How Many Ways to Arrange Five Colored Balls with Specific Conditions?

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SUMMARY

The discussion centers on calculating the number of ways to arrange five colored balls selected from a total of 30, with specific conditions requiring one blue, one red, and one yellow ball. The correct approach involves multiplying the number of arrangements for each colored ball (5 for blue, 4 for red, and 3 for yellow) and then multiplying by the permutations of the remaining two balls chosen from the remaining 27. The formula is confirmed as 5 * 4 * 3 * (27 Permute 2). Additionally, simulating this process using R for verification is recommended.

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erogard
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Hi, here's the question, I just need someone to confirm that I'm doing it right (been a while since my last stat class):

Let's say I have 30 balls all of different colors. I want to know in how many different ways I can align 5 balls picked at random (thus ordering matters). Note that one must be blue, one red and one yellow.

So let's start with the blue one. I have 5 different ways to arrange it (either place it first in line, or second, or third etc.). Then let's say I'm looking a the red one: I have 4 ways left to arrange it. Finally I have 3 slots left for the yellow one. Now for the remaining 2 balls, I still have 27 balls to choose from.

Would the answer be 5*4*3*(27 Permute 2)?

Thanks.
 
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Hey erogard.

That looks right to me.

Also if you want to test things like this, what I recommend you do is simulate the stochastic process in a computer package like R and then look at the probability of the event happening over say 10,000 or 100,000 iterations (which is quick with modern day computers).

This is always a good way for you to independently verify your own work.
 
How many balls are blue, red, and yellow within the 30 balls?
 

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