MHB How Many Ways to Fit Six People in Four Rooms?

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    2016
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The discussion focuses on the combinatorial problem of fitting six people into four rooms, each with a maximum capacity of four. Participants explore various methods to calculate the different arrangements possible under these constraints. The correct solution was provided by kaliprasad, who detailed the reasoning behind the calculations. The thread encourages engagement with the Problem of the Week format and highlights the importance of following the guidelines for participation. Overall, the discussion emphasizes mathematical reasoning and problem-solving techniques.
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Here is this week's POTW:

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In how many different ways can six people be accommodated in the four rooms, if each room can accommodate a maximum of four people?

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Congratulations to kaliprasad for his correct solution, which you can find as follows::)

Six persons can be accommodated in 4 rooms in $4^6=4096$ ways without any constraints.

We need to rule out the number of ways 6 or 5 persons can be accommodated in a room.

Number of ways 6 persons can be accommodated in one room = 4 as in 4 ways we can choose the room for all persons.

If one room has 5 persons, and the other one room has one person. Then the 5 persons can be chosen in 6 ways, and the room for 5 persons can be chosen in 4 ways and then room for one person can be chosen in 3 ways. So the number of ways for such cases $= 6 \times 4 \times 3 = 72$.

Therefore the number of ways atmost 4 persons can be in a room = 4096- 4 - 72 = 4020.
 
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