How Many Ways to Fit Six People in Four Rooms?

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    2016
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The problem discussed involves determining the number of ways to accommodate six people in four rooms, with each room having a maximum capacity of four people. The correct solution was provided by user kaliprasad, who utilized combinatorial mathematics to arrive at the answer. This problem exemplifies the application of permutations and combinations in real-world scenarios, particularly in resource allocation and space management.

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Here is this week's POTW:

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In how many different ways can six people be accommodated in the four rooms, if each room can accommodate a maximum of four people?

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Congratulations to kaliprasad for his correct solution, which you can find as follows::)

Six persons can be accommodated in 4 rooms in $4^6=4096$ ways without any constraints.

We need to rule out the number of ways 6 or 5 persons can be accommodated in a room.

Number of ways 6 persons can be accommodated in one room = 4 as in 4 ways we can choose the room for all persons.

If one room has 5 persons, and the other one room has one person. Then the 5 persons can be chosen in 6 ways, and the room for 5 persons can be chosen in 4 ways and then room for one person can be chosen in 3 ways. So the number of ways for such cases $= 6 \times 4 \times 3 = 72$.

Therefore the number of ways atmost 4 persons can be in a room = 4096- 4 - 72 = 4020.
 

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