The discussion revolves around the problem of forming a six-digit odd number that is less than 600,000 using the digits 1 through 9, with the condition that no digit may be repeated. Participants explore various approaches to calculate the total number of valid combinations.
Participants express differing views on the correct approach to calculating the total number of valid six-digit odd numbers less than 600,000, with no consensus reached on the final count or methodology.
Some calculations depend on the interpretation of how to handle the restrictions on digit selection, leading to potential variations in the total count. The discussion reflects uncertainty regarding the impact of digit repetition on the total combinations.
Punch said:A six-digit number is to be formed from the digits 1, 2 ,3, 4, 5, 6, 7, 8, 9. Find how many ways the six-digit number can be formed if the number must be odd and is less than 600,000 and no digit may appear more than once
grgrsanjay said:its a six digit number
1st digit can be 1,2,3,4,5
2nd digit can be 0-9
3rd digit can be 0-9
4th digit can be 0-9
5th digit can be 0-9
6th digit can be 1,3,5,7,9
total ways = 5(10)(10)(10)(10)(5)
The number is odd; the last digit must be 1, 3, 5, 7 or 9.A six-digit number is to be formed from the digits 1, 2 ,3, 4, 5, 6, 7, 8, 9.
Find how many ways the six-digit number can be formed if the number must be odd
and is less than 600,000 and no digit may appear more than once.