How many zeroes are at the end of (45^8)(88^5)

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Homework Help Overview

The problem involves determining the number of trailing zeroes in the expression (45^8)(88^5) without using a calculator. The subject area pertains to number theory and prime factorization.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss breaking down the numbers into their prime factors and how to calculate the number of factors of 10 that can be formed from those primes. There is an exploration of the relationship between the factors of 2 and 5 in the context of trailing zeroes.

Discussion Status

Some participants have provided guidance regarding the use of calculators and the implications of scientific notation on the perceived number of trailing zeroes. There is recognition of differing interpretations of the calculator's output, but no explicit consensus on the reasoning behind the original poster's confusion.

Contextual Notes

Participants note that the calculator may not display all digits of the product, leading to potential misunderstandings about the number of trailing zeroes. There is also mention of homework constraints regarding the use of calculators.

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Homework Statement



How many zeroes are at the end of (45^8)(88^5), don't use a calculator.

Homework Equations



Using the unique factorization of integers theorem, you can break any integer down into the product of prime integers.

The Attempt at a Solution



So I broke it down

(45^8) = (3 * 3 * 5) ^ 8
(88^5) = (2 * 2 * 2 * 11) ^ 5

If you put it back together as separate factors you get something like this

(3^16) * (5^8) * (2^15) * (11^5)

now my thinking is that you can find the number of zeroes by figuring out how many factors of 10 (which equals 2 * 5) you can make.

You can make 8 factors of 10 so it looks like
(3 ^ 16) * (2 ^ 7) * (11 ^ 5) * (10 ^ 8)

And from this I assume that there would be 8 zeroes at the end, however if you check it with a calculator you get a different answer..

(45^8) * (88^5) = 8.87387835 × 10^22

Anyone care to explain where my thinking is wrong..?
 
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You are right, but checking it with a calculator doesn't work because the screen of the calculator can't display all the digits of the product, if you use the calculator on your computer it should display the full number.
 
Animuo said:

Homework Statement



How many zeroes are at the %nd of (45^8)(88^5), don't use a calculator.

Homework Equations



Using the unique factorization of integers theorem, you can break any integer down into the product of prime integers.

The Attempt at a Solution



So I broke it down

(45^8) = (3 * 3 * 5) ^ 8
(88^5) = (2 * 2 * 2 * 11) ^ 5

If you put it back together as separate factors you get something like this

(3^16) * (5^8) * (2^15) * (11^5)

now my thinking is that you can find the number of zeroes by figuring out how many factors of 10 (which equals 2 * 5) you can make.

You can make 8 factors of 10 so it looks like
(3 ^ 16) * (2 ^ 7) * (11 ^ 5) * (10 ^ 8)

And from this I assume that there would be 8 zeroes at the end, however if you check it with a calculator you get a different answer..

(45^8) * (88^5) = 8.87387835 × 10^22

Anyone care to explain where my thinking is wrong..?

Your answer is right. The calculator is giving you a truncated answer in scientific notation. Even though the last shown figure is "5", there are still many nonzero figures to the right of that 5 when you write the whole number out. There will still be eight trailing zeroes.
 
Wow... didn't think of that, I used the google calculator and now I feel like a dumbass -.-. Thanks guys, feel better now. Here's another one I'm having a little difficulty with, and I don't feel like spamming these forums.

Moderator note: I made a separate thread for the new problem.[/color]
 
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