1. The problem statement, all variables and given/known data If a person has a mass of 68kg, how much does he weigh on the top of mount everest (8488km above sea level? Given: m=68kg, d=8488m 2. Relevant equations F = (G(m1)(m2)) / r^2 3. The attempt at a solution I tried figuring out the new radius. Once i get the radius i enter all the data and rearrange the formula to get m2 by itself. Fr^2/Gm1 = m2 My problem is getting the new radius.
Sorry, the old radius is the basic radius in the original formula. Its just r^2. But since im dealing with a new altitude doesn't it change?
You didn't understand my question. I'll take another tack. How much does the person weigh at sea level? Why?
As long as an object is at or near the surface of the celestial object and we know the value of g the gravitational field strength at the surface of the celestial body, we can use F= mg to find the weight of the object
Newton's universal law of gravitation, F=GMm/r^{2}, is not called universal just on a whim. In other words, it applies at sea level as well as atop Mt. Everest.
But the answers are different. My answer book tells me that the weight on the surface of the earth is 668 newtons and 664 newtons on mount Everest.