- #1
smillphysics
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A 57.0 kg circus performer oscillates up and down at the end of a long elastic rope at a rate of once every 7.20 s. The elastic rope obeys Hooke's Law. By how much is the rope extended beyond its unloaded length when the performer hangs at rest
T=2pi* sqrt m/k
kx=mg
7.2sec=2pi*sqrt 57/k, then sq. rt k= 2pi*sqrt 57/1.2 , I get k=4.2
then I put k into the second equation to get x=133m which is the wrong answer- What am I doing incorrectly?
T=2pi* sqrt m/k
kx=mg
7.2sec=2pi*sqrt 57/k, then sq. rt k= 2pi*sqrt 57/1.2 , I get k=4.2
then I put k into the second equation to get x=133m which is the wrong answer- What am I doing incorrectly?