How Much Energy Is Released When Mixing HCl and NaOH?

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SUMMARY

The enthalpy of neutralization for the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is established at -56 kJ/mol of water produced. In the given scenario, mixing 195.0 mL of 0.400 M HCl with 155.5 mL of 0.500 M NaOH results in a calculated energy release of -8.722 kJ. However, this calculation is incorrect due to the need to account for the limiting reactant in the reaction. A balanced chemical equation and the stoichiometry of the reactants must be considered to determine the correct amount of energy released.

PREREQUISITES
  • Understanding of stoichiometry in chemical reactions
  • Knowledge of enthalpy and thermodynamic principles
  • Familiarity with molarity calculations
  • Ability to balance chemical equations
NEXT STEPS
  • Review the concept of limiting reactants in chemical reactions
  • Learn how to balance chemical equations for acid-base reactions
  • Study the calculation of enthalpy changes in reactions
  • Explore the application of calorimetry in measuring energy changes
USEFUL FOR

Chemistry students, educators, and anyone involved in thermodynamics or chemical reaction analysis will benefit from this discussion.

JessicaHelena
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Homework Statement


The enthalpy of neutralization for the reaction of a strong acid with a strong base is -56 kJ/mol of water produced. How much energy will be released when 195.0 mL of 0.400 M HCl is mixed with 155.5 mL of 0.500 M NaOH?

Homework Equations


c=n/V

The Attempt at a Solution


to get n (from c=n/V), we can do c*V.
In this case, the total moles is then 0.4*.195 + .1555 * 0.5 moles
and multiplying that by -56kJ/mol gave me -8.722 kJ, but that's wrong... Why?
 
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Do all moles react ? Write out the 'reaction' equation and underneath put the # of moles for each.
 

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