Need help determining the molar enthelpy of Magnesium with HCl

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Discussion Overview

The discussion revolves around determining the molar enthalpy of combustion (ΔH(c)) of magnesium when reacted with hydrochloric acid (HCl). Participants explore the calculations involved, the application of Hess's Law, and the interpretation of experimental data related to the reactions of magnesium and magnesium oxide with HCl.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant presents a detailed calculation for the molar enthalpy of magnesium, including the mass of magnesium, the volume and concentration of HCl, and temperature changes during the reactions.
  • Another participant suggests that understanding Hess's Law is essential for solving the problem, implying that the calculations may not be valid without this understanding.
  • A later reply indicates that the participant has re-evaluated their calculations using Hess's Law and arrived at a different value for the molar enthalpy, specifically -563.7 kJ/mol.
  • Some participants express uncertainty about the data and calculations, with one mentioning a lack of clarity regarding Hess's Law and its application in this context.

Areas of Agreement / Disagreement

There is no consensus on the correct approach or final value for the molar enthalpy of magnesium. Participants express differing levels of understanding regarding Hess's Law and its relevance to the calculations presented.

Contextual Notes

Participants reference experimental data and calculations that may depend on specific assumptions about the reactions and conditions. The discussion includes unresolved aspects of the calculations and the application of Hess's Law.

Sythe777
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Picture to show more clearly: http://i.imgur.com/JmARtQM.png

1. Homework Statement

What is the molar enthalpy of combustion ΔH(c) of magnesium?

Mg(s) + 2HC(aq) → H2(g) + MgCl2(aq)

MgO(s) + 2HCl(aq) → H2O(l) + MgCl2(aq)

m(Mg) = 0.5 g
m(MgO) = 1.0 g
V(HCl) = 100.0 mL
C(HCl) = 1.0 mol/L
T(HCl) = 19° C
T(rxn1) = 38° C
T(rxn2) = 25° C

rxn1 relates to Mg(s) + 2HCl(aq)

rxn2 relates to MgO(s) + 2HCl(aq)2. Homework Equations

n(Mg) = m/M
q = mcΔT
ΔH(C) = -q/n

3. The Attempt at a Solution

n(Mg) = m/M
n(Mg) = (0.5 g)/(24.31 g/mol)
n(Mg) = 0.02056766762649115590292060880296 mol
n(Mg) = 0.021 mol

q = mcΔT
q = (3.6 g)(4.18 J/g °C)(38° C – 19° C)
q = 285.912 J
q = 285.9 J

ΔHC = -q/n
ΔHC = -285.9 J/0.021 mol
ΔHC = 13614.285714285714285714285714286
ΔHC = 13.6 kJ/mol

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If anyone can help me with this it would be greatly appreciated!
 
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Wouldn't hurt if you will explain what you are doing and what the data is about.

Do you know the Hess law?
 
My class touched on Hess's Law for a bit but not enough to make much of an impact on me. I would edited the post above, but it shows no edit button to use. Basically, I am finding the moles of magnesium for molar enthalpy and the heat quality of the HCl for the other part of molar enthalpy and plug values into the molar enthalpy equation.

Forgot to mention, the data above is experimental
 
Last edited:
This is a Hess law problem, so you can't solve it without understanding the Hess law.
 
all right, I think I've got it after checking with Hess's Law and doing a full solution.

this is what I have come up with: http://imgur.com/a/Cs95f (sorry, I am lazy)

overall, I got a value of -563.7 kJ/mol.
 

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