How Much Force to Apply on m1 to Make m2 Jump Off the Table?

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SUMMARY

The discussion focuses on calculating the force required to make mass m2 jump off a table when mass m1 is placed on top of a spring. The key equations referenced are Newton's second law and Hooke's law, specifically F > (m1 + m2) * g and F > m2 * g. The confusion arises from understanding the net force acting on m2 at the moment it is about to leave the table, emphasizing the need to consider both masses and gravitational force.

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Homework Statement



Hey there,

We assume that the spring got no mass and there are no frictions. If you want to push down just as hard on m1 that if you release ... m2 will be just about to jump and leave the table?


unbenannt_979.jpg


Homework Equations



Newton and Hooke are our very best friends :)

The Attempt at a Solution



1. F > (m1 + m2) * g

or

2. F > m2 * g ?

Im a bit confused, as m1 is already pushing on the string even if there is no extra force... but how much do I have to push down for myself on m1? My guess is that 1 would be to total amount of force "pulling" on m2, but the force needed to get this right, would be 2, as m1 is supporting.

Thanks in advance
 
Physics news on Phys.org
What is the condition that m2 jumps and leaves the table? What can you say about the net force acting on it at that instant?

ehild
 

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