# Friction/spring/inclined plane problem

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1. Jul 17, 2015

### Alex.malh

1. The problem statement, all variables and given/known data
There is a block of 1kg (m1) resting frictionless on another block of 5kg (m2). m1 is connected by a horizontal spring to m2. m2 is resting on an inclined plane of 45°. Between m2 and the plane there is friction.
A force of 200N is applied on m2, pushing it upwards.

F=200N, m1=1kg, m2=5kg, f=0.2, k=100N/m, initial spring length= 0.20m, g=10m/s²

What is the spring length at equilibrium?

2. Relevant equations
F=m*a
F=k*spring length
Friction W= (reaction force R)*f

3. The attempt at a solution
Increase in spring length = l
F - w*cos45 - R*cos45 - k*l = (m1+m2)*a
m1*g + m2*g - w*sin45 - R*sin45 = 0
w=0.2*R
k*l=m1*a

Solving this i get a=20m/s² which can't be right.

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2. Jul 17, 2015

### Qwertywerty

Why do you add k*l in 1st equation ??

You should be writing 1st equation considering both blocks together as one system . You will then not get k*l in the equation .

The rest seems fine .

3. Jul 17, 2015

### haruspex

As qwertywerty notes, that kl term should not be there. That is internal to the two-mass system.
But the second equation looks wrong too. Check the signs, and consider what the vertical acceleration is.

4. Jul 17, 2015

### Qwertywerty

You're right - my bad . So you would have to consider some net acceleration and write horizontal and vertical accelarations in it's terms .

5. Jul 20, 2015

### Alex.malh

New equations:
F - w*cos45 - R*cos45 = (m1+m2)*ah
(m1+m2)*g + w*sin45 - R*sin45 = (m1+m2) *av
w=0.2*R

Now to solve this i'm still missing a relationship between ah and av.
I've taken av = ah ( angle is 45°, if the block has moved 1m to the right, it will have moved the same distance vertically, xv = xh -> av = ah)
Now i end up with R=495N and a=36.7m/s²

Not possible imo.
Do you guys see where i go wrong?

thanks!

regards,

6. Jul 20, 2015

### Qwertywerty

Would you check your calculations ?

7. Jul 20, 2015

### Staff: Mentor

In your second equation, you have the wrong sign on the ma term. The blocks are accelerating vertically upward. The way you have it, av = - ah

Chet

8. Jul 20, 2015

### Alex.malh

Ah yes of course. Well, i've got it now. 7cm spring elongation :)
Thx a lot!