How Much Ice Melts When a Bullet Penetrates It?

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SUMMARY

The discussion focuses on calculating the amount of ice melted when a 70-gram bullet traveling at 250 m/s penetrates a block of ice at 0 degrees Celsius. The key concepts include the energy transfer from the bullet to the ice and the latent heat of fusion required to melt ice. The energy needed to melt one gram of ice is 334 Joules, and the kinetic energy of the bullet can be calculated using the formula KE = 0.5 * m * v², resulting in a total energy transfer that can be used to determine the mass of ice melted.

PREREQUISITES
  • Understanding of kinetic energy calculations
  • Knowledge of latent heat of fusion for ice
  • Basic principles of thermodynamics
  • Ability to perform unit conversions (grams to kilograms)
NEXT STEPS
  • Calculate the kinetic energy of the bullet using KE = 0.5 * m * v²
  • Research the latent heat of fusion for ice (334 J/g)
  • Determine the mass of ice melted using the energy transfer from the bullet
  • Explore the effects of temperature changes on the melting process
USEFUL FOR

Students in physics or engineering courses, educators teaching thermodynamics, and anyone interested in the practical applications of energy transfer and phase changes in materials.

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Please help...How much ice melts?

Homework Statement


A 70 gram bullet traveling at 250 m/s penetrates a block of ice at 0 degrees Celsius and comes to rest within the ice. Assuming that the temperature of the bullet doesn't change appreciably, how much ice is melted as a result of the collision?

The Attempt at a Solution


I don't know where to start on this?
 
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Questions to get you started:

How much energy is needed to melt a gram of ice?

How much energy does the bullet give to the block of ice when it slows down?
 

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