How Much Ice Melts from a Sliding Block's Kinetic Energy?

[chops369]

Homework Statement

A 2.5 kg block of ice at a temperature of zero degrees celsius and an initial speed of 5.7 m/s slides across a level floor. If 3.3 x 10⁵ J are required to melt 1 kg of ice, how much ice melts, assuming that the initial kinetic energy of the ice block is entirely converted to the ice's internal energy?

Homework Equations

I think I need to use PE + KE + U = 0

The Attempt at a Solution

I have no idea where to even begin :(

 

[Queue]

Homework Statement

A 2.5 kg block of ice at a temperature of zero degrees celsius and an initial speed of 5.7 m/s slides across a level floor. If 3.3 x 10⁵ J are required to melt 1 kg of ice, how much ice melts, assuming that the initial kinetic energy of the ice block is entirely converted to the ice's internal energy?

Homework Equations

I think I need to use PE + KE + U = 0

The Attempt at a Solution

I have no idea where to even begin :(

Well the formula for kinetic energy of a body is KE = .5mv². So how much kinetic energy do we have in the block at the start? If you assume all of that gets transferred into heat energy how much ice did it melt?

 

[chops369]

Ok, so I used KE = .5mv² and found that the ice has an initial KE of 41 J. Then I did 41 / 3.3 x 10⁵ and I concluded that .0000124 kg of ice melted. Is this correct?

 

[Queue]

Ok, so I used KE = .5mv² and found that the ice has an initial KE of 41 J. Then I did 41 / 3.3 x 10⁵ and I concluded that .0000124 kg of ice melted. Is this correct?

Sounds correct to me.

 

[chops369]

Great, thanks a lot.