How much ice must melt at 0 deg. C to gain 6 g of mass?

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Homework Help Overview

The problem involves determining the amount of ice that must melt at 0 degrees Celsius to achieve a mass gain of 6 grams. The context relates to concepts of phase change and energy absorption during melting.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of energy equations, including E=mc², and the latent heat of fusion for ice. There are attempts to relate energy absorbed during melting to the mass of ice required.

Discussion Status

The discussion includes various interpretations of the problem and approaches to finding a solution. Some participants express uncertainty about the equations needed, while others suggest potential methods for calculation. There is no explicit consensus on the correct approach, but several lines of reasoning are being explored.

Contextual Notes

Participants note the importance of adhering to forum rules regarding the provision of complete answers in homework help threads, indicating a focus on guiding understanding rather than providing direct solutions.

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Homework Statement


This is all that is given.

How much ice must melt at 0 deg. C to gain 6 g of mass?

Homework Equations


I don't know any Relevant equations to this problem.


The Attempt at a Solution




I have tried leaving mass as a variable and using Latent Heat Energys too. I have no idea what to set equal to what because i don't have equations to work with this problem.
 
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Hmm I think some use of E=mc2 is needed here. If you can find the energy of 6g then assume that is the energy 'absorbed' by a block of ice to turn it to water.
 
Huh?

Kurdt said:
Hmm I think some use of E=mc2 is needed here. If you can find the energy of 6g then assume that is the energy 'absorbed' by a block of ice to turn it to water.

When the ice melts, energy is absorbed. I get an equiv of 6g = 1.3e14 cal and it takes 79.71 cal/g to melt ice. So it seems to require 1.617e6 metric tons, a cube about 117 m on a side.
 
rdx said:
When the ice melts, energy is absorbed. I get an equiv of 6g = 1.3e14 cal and it takes 79.71 cal/g to melt ice. So it seems to require 1.617e6 metric tons, a cube about 117 m on a side.

Well that's how I'd do it. If you can see any other intention in the question please feel free to contribute.

I must say if you're going to post in other peoples threads in the homework section. Do not post what could be considered full answers as this is against the rules (even if you have doubts over the method).
 
Kurdt said:
Well that's how I'd do it. If you can see any other intention in the question please feel free to contribute.

I must say if you're going to post in other peoples threads in the homework section. Do not post what could be considered full answers as this is against the rules (even if you have doubts over the method).

"Against the rules?" How very strange. I seems to assume a monolithic learning style. Where rules?
 

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