How Much Netting Does Rita Need to Cover a Rectangular Area?

[mathdad]

Rita wants to cover a roughly rectangular area with netting. The height is 9 feet (but one side is along a solid fence, so could be 4 feet), two sides are each 6 feet, and the other side is 5_1/2 feet. How much netting does she need? Netting comes as a rectangular or square piece.

My Work:Let A = rectangular surface area Use the formula: A = 2(wh + Lh + Lh) Rewrite 5_1/2 as 11/2 for easy calculation. If the height is 9 feet, use the following set up: A = 2[(11/2)(9) + (6)(9) + (6)(9)] If the height is 4 feet, use the following set up: A = 2[(4)(9) + (6)(9) + (6)(9)]

Is any of this right?

 

[HallsofIvy]

I do not understand exactly what you are asking. You say "Rita wants to cover a roughly rectangular area with netting" so I would have thought that you wanted to find the area of that "roughly[ rectangular" region. But then you talk about the "height" and a "solid fence". Are you putting netting around the fence and giving the height of the fence? You say "let A = rectangular surface area?" So are you talking covering a rectangular solid, not a "rectangular area"?

 

[mathdad]

I do not understand exactly what you are asking. You say "Rita wants to cover a roughly rectangular area with netting" so I would have thought that you wanted to find the area of that "roughly[ rectangular" region. But then you talk about the "height" and a "solid fence". Are you putting netting around the fence and giving the height of the fence? You say "let A = rectangular surface area?" So are you talking covering a rectangular solid, not a "rectangular area"?

I found this question online.