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How much perspiration must vaporize per hour to dissipate extra energy

  1. Jun 7, 2016 #1
    1. The problem statement, all variables and given/known data

    During the game, the metabolism of basketball players often increases by as much as 30.0 W. How much perspiration must a player vaporize per hour to dissipate this extra thermal energy? Assume that perspiration is simply pure water and that perspiration starts at temperature of 37 degrees celcius.

    2. Relevant equations


    3. The attempt at a solution

    Thermal energy to be dissipated in 1.00h is

    The amount of water this energy transmittes as heat would vaporize is,
    m=(1.08x10^5J)/(2.26X10^6J/kg)= 4.78x10^-2kg

    I'm not sure if I'm doing it correctly. I never used 37 degrees/
  2. jcsd
  3. Jun 8, 2016 #2


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    Staff: Mentor

    Did you have body temperatures in previous problems? Maybe the players start at lower temperatures?
  4. Jun 8, 2016 #3


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    Staff: Mentor

    You use 37° when reading from tables to determine what value of ∆Hvap to use because it is not a fixed value across all temperatures, ∆Hvap falls slightly as temperature rises. http://www.thermexcel.com/english/tables/vap_eau.htm
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