1. The problem statement, all variables and given/known data During the game, the metabolism of basketball players often increases by as much as 30.0 W. How much perspiration must a player vaporize per hour to dissipate this extra thermal energy? Assume that perspiration is simply pure water and that perspiration starts at temperature of 37 degrees celcius. 2. Relevant equations Q=mcΔT Q=mHv 3. The attempt at a solution Thermal energy to be dissipated in 1.00h is U=(30J/s)(3600s/h)=1.08x10^5J The amount of water this energy transmittes as heat would vaporize is, m=(1.08x10^5J)/(2.26X10^6J/kg)= 4.78x10^-2kg ----> Just looking for someone to double check my reasoning/calculations and to make sure the number of significant figures has been respected. Thank you so much in advance!