1. The problem statement, all variables and given/known data Two cars are parked beside each other, facing in opposite directions. Car 1 accelerates at 5m/s^2 up to a max. speed of 25m/s, and Car 2 accelerates at 4m/s^2 up to a max. speed of 24m/s. How much time has elapsed when the cars are 200m apart? 2. Relevant equations v=d/t vf^2=vi^2+2ad 3. The attempt at a solution Car 2 ------ 576=8d d=72m it takes car 2 3seconds to travel 72m Car1 -------- 625=10d d=62.5m it takes car 1 2.50seconds to travel 62.5m So, the cars are 134.5m apart at this stage. They need to travel 200m-134.5m=65.5m before they are 200m apart. So, if car 1 needs to travel 65.5m then this distance will take 65.5/25 = 2.62seconds So, if car 2 needs to travel 65.5m then this distance will take 65.5/24 = 2.73seconds This is as far as I could get. The answer is 6.83seconds. Please help me understand how they arrived at this solution? Thank you.