Kinematics Homework Help (2D motion)-Stopping over time

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SUMMARY

The discussion focuses on a kinematics problem involving 2D motion, specifically calculating stopping distance and maximum speed to avoid hitting a deer. The initial speed of the car is 18 m/s, with a reaction time of 0.5 seconds and a maximum deceleration of 12 m/s². The correct stopping distance is determined to be 19 meters, while the maximum speed to avoid collision is 25 m/s. The participant's calculations initially led to different results, highlighting the importance of accurately accounting for reaction time and applying the correct kinematic equations.

PREREQUISITES
  • Understanding of kinematic equations, specifically vf² = vo² + 2ad
  • Knowledge of basic physics concepts such as speed, distance, and acceleration
  • Familiarity with the concept of reaction time in motion scenarios
  • Ability to perform calculations involving deceleration and distance
NEXT STEPS
  • Study the derivation and application of kinematic equations in various motion scenarios
  • Learn about the effects of reaction time on stopping distances in real-world driving situations
  • Explore advanced topics in physics such as dynamics and forces affecting motion
  • Practice solving similar problems involving 2D motion and collision avoidance
USEFUL FOR

This discussion is beneficial for students studying physics, particularly those focusing on kinematics, as well as educators looking for practical examples to illustrate motion concepts. It is also useful for drivers interested in understanding the physics of stopping distances and safety measures on the road.

ithrowboxes
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Homework Statement



You're driving down the highway late one night at 18m/s when a deer steps onto the road 41m in front of you. Your reaction time before stepping on the brakes is 0.5s and the maximum deceleration of your car is 12 m/s/s

Homework Equations



1) How much distance is between you and the deer when you come to a stop?
2) What is the maximum speed you could have and still not hit the deer?

The Attempt at a Solution



Am I doing this right? She gives us the answer of 19m for the 1st question and 25m/s for the 2nd question. But I am coming up with a different answer for the first question.

First I figured the distance between the car and deer to be 36m, after you take into account the 0.5s reaction time. Then I started to calculate distance it takes to stop.

The equation I used was vf2 = vo2+2*a*d

I plugged in the variables to get 0m2/s2 = 324m2/s2 + (-24m2/s2)*d ... I solve for d to get 13.5m, which is the distance traveled. Take 36m - 13.5m to get 22.5m from the deer, not 19m. I have not attempted the 2nd question yet because I thought I may be doing something incorrect.
 
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ithrowboxes said:
[
First I figured the distance between the car and deer to be 36m, after you take into account the 0.5s reaction time. Then I started to calculate distance it takes to stop.
.

That should be 32.
 

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