dimmaz88
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How much weight could this hold?
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How would you go about figuring that out?
dimmaz88
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Sorry I should of added more detail. Imagine it's a chain link vertically, and it's under tension.
dimmaz88
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Sorry I meant horizontally, I'm really tired tonight lol. It's part of a slackline setup.
dimmaz88
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Erm..not quite lol. I hope it wouldn't combust.
dimmaz88 said:
The problem is, we can't discuss potentially dangerous activities here on the PF (that's in the Rules link at the top of the page under Info). If you don't have the background to do the calculation yourself, it's probably not a good idea for you to be trying to make a DIY slackline setup. Aren't there commercially available slackline setups that have different weight ratings?
dimmaz88
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I thought there might be some materials software for working out things like this. I know this would take plenty of tension, I just wondered if I could work out how much.
If I compare the dimensions to avaliable items, this is overkill (comparison with a quick link for example).
If I compare the dimensions to avaliable items, this is overkill (comparison with a quick link for example).
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Can't tell how much this piece will hold ... there's no diameter shown for the holes nor their location relative to the sides of the piece.
dimmaz88
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dimmaz88
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SteamKing said:
Is it possible to calculate now you have dimensions?
Lok
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Now for a quickie eyeballing (which you should never ever do without testing the part afterwards) calculation.dimmaz88 said:
The thinnest section is a cut out through a hole and has a surface Area of 25*(9+9)=450mm^2.
Now the worst construction steel in the world S185 (there could be something worse than this) has a Yield Strength of 175-185N/mm^2.
That would give a 8 metric tonnes. So With a safety factor of 4 (as clearly you will be next to it in use) you could say it has a maximum strength of 2 tonnes.
All the above are with loads of assumptions.
Because Engineering is more about practice in hopes of avoiding the math, never use a part in a life threatening situation that has not been subjected to failure testing. Not sure how considering the strength of it.
Also if you know your mild steels yield strength you could do the math again and get a more real result.
dimmaz88
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Wow, thanks Lok. That's a great answer.
Would you mind explaining the (25*(9+9)=450mm^2).
I find this really interesting, I'll have to read more on the subject. I assume the size of the pin that passes through the hole makes a difference too?
Would you mind explaining the (25*(9+9)=450mm^2).
I find this really interesting, I'll have to read more on the subject. I assume the size of the pin that passes through the hole makes a difference too?