The work done in firing a 2.0 kg projectile at an initial speed of 50 m/s is calculated using the work-energy theorem, resulting in 2500 Joules. The formula used is K = 1/2mv², where m is the mass and v is the velocity. This approach simplifies the calculation by directly relating kinetic energy to work done, bypassing more complex methods involving force and distance. Neglecting air resistance is crucial for this calculation to hold true.
PREREQUISITESStudents in physics courses, educators teaching mechanics, and anyone interested in understanding the principles of work and energy in projectile motion.
It only seems easy because you were able to astutely note that the work-energy theorem would give you the answer for total work done. Others might have tried to find force/distance/acceleration etc., to use in calculating the work done, but to no avail.mmiller9913 said:Homework Statement
Determine the amount of work done in firing a 2.0-kg projectile with an initial speed of 50 m/s. Neglect any effects due to air resistance
Homework Equations
W = delta K
K = 1/2mv^2
The Attempt at a Solution
just take K= 1/2(2)(50)^2 to get 2500 J[/color]...it seems to easy?