How Much Work Does It Take to Pull a Skier Up a Slope?

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SUMMARY

The discussion focuses on calculating the work required to pull a skier of mass 70.0 kg up a 30-degree slope over a distance of 60.0 meters using a motor-driven cable. The correct approach involves using the gravitational potential energy formula rather than incorrectly calculating force in Joules. The key equation for work is W = F (delta)r cos(theta), where the force must be calculated in Newtons, not Joules. The gravitational potential energy change provides a more straightforward solution to the problem.

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Homework Statement


A skier of mass 70.0 kg is pulled up a slope by a motor-driven cable.
How much work is required to pull the skiera distance of 60.0m up a 30 degree slope (assumed frictionless) at a constant speed of 2.00 m/s?


Homework Equations


W=F (delta)r cos(theta)


The Attempt at a Solution


(delta)r= 60.0m
(theta)=30.0 degrees
Force=60sin30=30 J


Is this the correct start?
 
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scurry18 said:

Homework Statement


A skier of mass 70.0 kg is pulled up a slope by a motor-driven cable.
How much work is required to pull the skiera distance of 60.0m up a 30 degree slope (assumed frictionless) at a constant speed of 2.00 m/s?


Homework Equations


W=F (delta)r cos(theta)


The Attempt at a Solution


(delta)r= 60.0m
(theta)=30.0 degrees
It's all good up until this point:
scurry18 said:
Force=60sin30=30 J
Firstly force is measured in Newton's and not Joule's. Secondly, how did you calculate the force acting on the skier?

HINT: This problem is much more straight forward if one simply considered the gravitational potential energy of the skier.
 

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