How much work is done on the ball during the acceleration?

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SUMMARY

The discussion focuses on calculating the work done on a 0.50 kg ball accelerated by an 8.0 N force over a distance of 3.0 m. The participant initially misapplied the kinetic energy formula, assuming the velocity was zero. However, using the work-energy theorem, it is established that the work done on the ball equals its kinetic energy, which must be calculated based on the force applied and the distance moved.

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  • Understanding of Newton's Second Law of Motion
  • Familiarity with the work-energy theorem
  • Knowledge of kinetic energy calculations
  • Basic algebra for solving equations
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  • Learn how to calculate work done using force and distance
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of applying the work-energy theorem in problem-solving.

kelly242
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Homework Statement



A 0.50 kg ball accelerated from rest by a 8.0 N force for 3.0 m

Homework Equations



W=E
Ek= 1/2mv2
Ep=mgh

The Attempt at a Solution


Given: mass= 0.50 Kg, V=0m/s, F=8.0 N, d=3.0 m

Ek=1/2mv2
=1/2(0.50 kg)(0 m/s)2
=o J
That's wrong
 
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How can v be 0 if the ball is being accelerated for a finite period of time? Use the work-energy theorem to calculate the amount of work done on the ball. Since nothing else contributes to the ball's energy, this work must be its kinetic energy.
 

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