1. The problem statement, all variables and given/known data A 45 kg steel ball is projected vertically with an initial speed of 280 m s . While the ball is rising, 8.5E5 J of heat energy are produced due to air friction. What is the maximum height reached by the ball? 2. Relevant equations Ek = 1/2mv^2 Ep = mgh 3. The attempt at a solution I started with Ekbefore=Epafter+Ekafter-Eheat so It'll be 1/2(45kg)(280m/s) = (45kg)(9.8m/s^2)h + 1/2(45kg)(0) - 8.5E5 J Solving for H, I got 5927.44 m, the answer is 2100m (rounded), am I suppose to add the heat energy or subtract it from the energy after?