How much work was done by the tension in the cable?

  • #1
I think I have been staring at this question too long as I can not figure it out. I am sure the answer is simple:

A 1500-kg elevator moves upward with a constant speed through a vertical distance of 25m. How much work was done by the tension in the cable?

I know that W= (F cos 0)s, and that F= ma. What I can't figure out is the acceleration. It doesn't have one as it is moving with a constant speed. Any info on where to start?
 

Answers and Replies

  • #2
StatusX
Homework Helper
2,564
1
F=ma when F is the total force on the object. Here, the total force is 0, since the object isn't accelerating, and so the tension in the cable must exactly balance the force of gravity.
 
  • #3
So F= 0 and T= mg?
 
  • #4
StatusX
Homework Helper
2,564
1
Yea, if F is the total force on the object (you can always use F to stand for only one contribution to the force, it's just then F=ma won't hold).
 

Related Threads on How much work was done by the tension in the cable?

  • Last Post
Replies
13
Views
7K
  • Last Post
Replies
1
Views
4K
Replies
1
Views
2K
Replies
11
Views
1K
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
6
Views
3K
Replies
4
Views
20K
Replies
2
Views
2K
Replies
2
Views
2K
Replies
7
Views
8K
Top