How should I interpret a formula without brackets?

[Samwise-zambeezi]

Hi all,

I have a formula which i might have expected to have brackets, but it hasn't, so i need to correctly interpret it.

Could anyone please offer any pointers as to how it should read?

The formula is '1.2 . h - 0.2 . x'

Can i assume that it should be '(1.2 . h) - (0.2 . x)'?

Thanks

Zamb

 

[HallsofIvy]

You don't really need to "assume" that. Remember "PEMDAS" ("Please Excuse my dear aunt Sally")- Parentheses, Exponents, Multiplication, Division, Addition, Subtration. Multiplication and division have precedence over addition and subtraction.

 

[topsquark]

Hi all,

I have a formula which i might have expected to have brackets, but it hasn't, so i need to correctly interpret it.

Could anyone please offer any pointers as to how it should read?

The formula is '1.2 . h - 0.2 . x'

Can i assume that it should be '(1.2 . h) - (0.2 . x)'?

Thanks

Zamb

To be a bit more direct,.. Yes, that would be correct. However I still don't like it because it really reads 1*2*h - 0*2*x. Never use "." for multiplication unless you have defined it unambiguously!

-Dan

 

[Samwise-zambeezi]

Hi both,

thanks a lot for your feedback, much appreciated,

Zambeezi