How Should Uncertainties Be Represented When Significant Figures Differ?

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SUMMARY

The discussion focuses on how to represent uncertainties in calculations when the significant figures of the resultant uncertainty differ from those of the resultant number. Specifically, the example of dividing 5.40±0.10 by 90.00±0.05 yields a result of 0.06±0.001. Participants concluded that the uncertainty should reflect the significant figures of the least precise measurement, leading to the representation of 0.06±0.2 as the correct format, due to the two significant figures in the uncertainty derived from the original measurements.

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Homework Statement


When doing operations with numbers with uncertainties, if the significant figures of the resultant number's uncertainty is lower the significant figures of the resultant number, how should I show the resultant uncertainty. For example,


Homework Equations


if you do the operation 5.40+-0.10 / 90.00+-0.05 , the result is
0.06+-0.001


The Attempt at a Solution


the solution must either be
0.06 +- 0.00

or

0.06 +- 0.01x(10^(-1))

since the number of the significant numbers should be equal. so which one is it?
 
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nrslmz said:

Homework Statement


When doing operations with numbers with uncertainties, if the significant figures of the resultant number's uncertainty is lower the significant figures of the resultant number, how should I show the resultant uncertainty. For example,


Homework Equations


if you do the operation 5.40+-0.10 / 90.00+-0.05 , the result is
0.06+-0.001




The Attempt at a Solution


the solution must either be
0.06 +- 0.00

or

0.06 +- 0.01x(10^(-1))

since the number of the significant numbers should be equal. so which one is it?
That "5.40+-0.10" is a little misleading. Although 5.40 is written as if it had 3 significant figures, that +-0.10 says that is is uncertain in the tenths place and so only has 2 significant figures. One way to do this is to calculate the largest possible value: 5.5/90.05= 0.6111 and smallest value: 5.3/89.95= 0.05886 That can be written as 0.06+-0.2.
 

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