How Thick is the Oil Layer for Strong Reflection of Green Light?

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SUMMARY

The discussion focuses on calculating the thickness of an oil layer that strongly reflects green light, specifically at a wavelength of 556 nm. The initial attempt incorrectly used the refractive indices of oil and water instead of air and oil. The correct approach involves using the formula for thin film interference, where the thickness (t) is determined by the equation t = mλ/2, with λ adjusted for the medium. The final correct thickness of the oil layer is 222 nm, aligning with the textbook answer.

PREREQUISITES
  • Understanding of thin film interference principles
  • Knowledge of refractive indices (n oil, n water, n air)
  • Familiarity with wavelength adjustments in different media
  • Ability to apply formulas for calculating film thickness
NEXT STEPS
  • Study the principles of thin film interference in detail
  • Learn how to calculate effective wavelengths in different media
  • Explore examples of interference patterns in various materials
  • Practice problems involving refractive indices and film thickness calculations
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High school physics students, educators teaching optics, and anyone interested in understanding thin film interference and its applications in real-world scenarios.

Terraist
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Hi, I'm a high school physics student and I'm having a lot of trouble with thin film interference

Homework Statement



A thin layer of oil (noil=1.25) is floating on water (n=1.33). How thick is the oil in the region that strongly reflects green light (λ=556nm)?

Homework Equations



noil/nwater = λwater/λoil

t = mλ/2, where t is thickness of the film, m is order of interference maxima (i'm not sure about this one)

The Attempt at a Solution



1.25/1.33 = 556/λ
λ=592 nm

t=mλ/2
=(1)(592)/2
=296 nm

(ans in book 222 nm)

I'm not entirely sure of what I'm doing here. I'm trying to just find the right formula to plug the variables in and I don't grasp the principles behind it. If someone could shed some light on the subject and provide some tips on how to solve similar problems it would be greatly appreciated.
 
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Everything is right except you're not supposed to use n oil and water but rather n air and oil, because the ray is coming from above in air and not from the water right?( I think this is a trick question or something) So your new wavelength would be 556/1.33 (n air is 1) = 444 and you should get the books answer.
 

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